[keek] extract uploader and uploader id with _search_regex

pull/8/head
remitamine 9 years ago committed by Sergey M․
parent f30e9976d6
commit 98e1c935a1

@ -1,8 +1,6 @@
# coding: utf-8
from __future__ import unicode_literals
import re
from .common import InfoExtractor
@ -26,10 +24,6 @@ class KeekIE(InfoExtractor):
video_id = self._match_id(url)
webpage = self._download_webpage(url, video_id)
uploader = uploader_id = None
matches = re.search(r'data-username="(?P<uploader>[^"]+)"[^>]*data-user-id="(?P<uploader_id>[^"]+)"', webpage)
if matches:
uploader, uploader_id = matches.groups()
return {
'id': video_id,
@ -38,6 +32,6 @@ class KeekIE(InfoExtractor):
'title': self._og_search_title(webpage),
'description': self._og_search_description(webpage),
'thumbnail': self._og_search_thumbnail(webpage),
'uploader': uploader,
'uploader_id': uploader_id,
'uploader': self._search_regex(r'data-username="([^"]+)"', webpage, 'uploader', None),
'uploader_id': self._search_regex(r'data-user-id="([^"]+)"', webpage, 'uploader id', None),
}

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