[utils] `format_decimal_suffix`: Fix for very large numbers (#3109)

Authored by: s0u1h
pull/3048/head^2
s0u1h 3 years ago committed by GitHub
parent 0c14d66ad9
commit eeb2a770f3
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@ -1780,6 +1780,7 @@ Line 1
self.assertEqual(format_bytes(1024**6), '1.00EiB') self.assertEqual(format_bytes(1024**6), '1.00EiB')
self.assertEqual(format_bytes(1024**7), '1.00ZiB') self.assertEqual(format_bytes(1024**7), '1.00ZiB')
self.assertEqual(format_bytes(1024**8), '1.00YiB') self.assertEqual(format_bytes(1024**8), '1.00YiB')
self.assertEqual(format_bytes(1024**9), '1024.00YiB')
def test_hide_login_info(self): def test_hide_login_info(self):
self.assertEqual(Config.hide_login_info(['-u', 'foo', '-p', 'bar']), self.assertEqual(Config.hide_login_info(['-u', 'foo', '-p', 'bar']),

@ -2279,8 +2279,9 @@ def format_decimal_suffix(num, fmt='%d%s', *, factor=1000):
num, factor = float_or_none(num), float(factor) num, factor = float_or_none(num), float(factor)
if num is None or num < 0: if num is None or num < 0:
return None return None
exponent = 0 if num == 0 else int(math.log(num, factor)) POSSIBLE_SUFFIXES = 'kMGTPEZY'
suffix = ['', *'kMGTPEZY'][exponent] exponent = 0 if num == 0 else min(int(math.log(num, factor)), len(POSSIBLE_SUFFIXES))
suffix = ['', *POSSIBLE_SUFFIXES][exponent]
if factor == 1024: if factor == 1024:
suffix = {'k': 'Ki', '': ''}.get(suffix, f'{suffix}i') suffix = {'k': 'Ki', '': ''}.get(suffix, f'{suffix}i')
converted = num / (factor ** exponent) converted = num / (factor ** exponent)

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