odo extraction: Look for digit y-level for all main digits together

They should all be at the same y level, and the extra data helps avoid traps
when the digit has few pixels (eg. a 1).
pull/361/head
Mike Lang 1 year ago
parent 30f05b0656
commit a4eceea958

@ -50,39 +50,48 @@ def extract_odo(image):
return image.crop(ODO_COORDS) return image.crop(ODO_COORDS)
def get_brightest_region(image, xs, height):
"""For given image, return the sub-image of given height with the brightest
values for all the pixels at given x positions within the row."""
# Calculate total brightness by row
rows = [
sum(image.getpixel((x, y)) for x in xs)
for y in range(image.height)
]
# Find brightest sub-image of `height` rows
start_at = max(range(image.height - (height-1)), key=lambda y: sum(rows[y:y+height]))
# Cut image to only be that part
return image.crop((0, start_at, image.width, start_at + height))
def extract_digits(image, include_last=True): def extract_digits(image, include_last=True):
"""Takes an odo box, and returns a list of 9x6 digit images""" """Takes an odo box, and returns a list of digit images"""
# convert to greyscale # convert to greyscale
image = image.convert(mode='L') image = image.convert(mode='L')
# Find main digits y position
digit_xs = [
x + dx
for x in DIGIT_X_COORDS
for dx in range(DIGIT_WIDTH)
]
main_digits = get_brightest_region(image, digit_xs, DIGIT_HEIGHT)
digits = [] digits = []
for i, x in enumerate(DIGIT_X_COORDS): for i, x in enumerate(DIGIT_X_COORDS[:-1]):
# last digit is special digit = main_digits.crop((x, 0, x + DIGIT_WIDTH, main_digits.height))
is_last = i == len(DIGIT_X_COORDS) - 1 digits.append(normalize_digit(digit))
if is_last and not include_last:
continue
digit = image.crop((x, 0, x + DIGIT_WIDTH, image.height))
digits.append(normalize_digit(digit, is_last))
return digits
if include_last:
x = DIGIT_X_COORDS[-1]
last_digit = get_brightest_region(image, range(x, x + DIGIT_WIDTH), LAST_DIGIT_HEIGHT)
last_digit = last_digit.crop((x, 0, x + DIGIT_WIDTH, last_digit.height))
digits.append(normalize_digit(last_digit))
def normalize_digit(digit, is_last=False): return digits
# Calculate total brightness by row
rows = [
sum(digit.getpixel((x, y)) for x in range(digit.width))
for y in range(digit.height)
]
# Find brightest sub-image of DIGIT_HEIGHT rows
h = LAST_DIGIT_HEIGHT if is_last else DIGIT_HEIGHT
start_at = max(range(digit.height - (h-1)), key=lambda y: sum(rows[y:y+h]))
# Cut image to only be that part
digit = digit.crop((0, start_at, digit.width, start_at + h))
# Last digit is inverted - by looking for brightest sub-image we've likely found
# the section that has a white background. Now we want to normalize that so it looks like
# other images.
if is_last:
digit = digit.point(lambda v: 255 - v)
def normalize_digit(digit):
# Expand the range of the image so that the darkest pixel becomes black # Expand the range of the image so that the darkest pixel becomes black
# and the lightest becomes white # and the lightest becomes white
_min, _max = digit.getextrema() _min, _max = digit.getextrema()

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